3x^(1/2)-7x^(1/4)+3=0

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Solution for 3x^(1/2)-7x^(1/4)+3=0 equation:


D( x )

x < 0

x < 0

x in <0:+oo)

3*x^(1/2)-(7*x^(1/4))+3 = 0

3*x^(1/2)-7*x^(1/4)+3 = 0

t_1 = x^(1/4)

3*t_1^2-7*t_1^1+3 = 0

3*t_1^2-7*t_1+3 = 0

DELTA = (-7)^2-(3*3*4)

DELTA = 13

DELTA > 0

t_1 = (13^(1/2)+7)/(2*3) or t_1 = (7-13^(1/2))/(2*3)

t_1 = (13^(1/2)+7)/6 or t_1 = (7-13^(1/2))/6

t_1 = (7-13^(1/2))/6

x^(1/4)-((7-13^(1/2))/6) = 0

1*x^(1/4) = (7-13^(1/2))/6 // : 1

x^(1/4) = (7-13^(1/2))/6

x^(1/4) = (7-13^(1/2))/6 // ^ 4

x = ((7-13^(1/2))^4)/1296

t_1 = (13^(1/2)+7)/6

x^(1/4)-((13^(1/2)+7)/6) = 0

1*x^(1/4) = (13^(1/2)+7)/6 // : 1

x^(1/4) = (13^(1/2)+7)/6

x^(1/4) = (13^(1/2)+7)/6 // ^ 4

x = ((13^(1/2)+7)^4)/1296

x in { ((7-13^(1/2))^4)/1296, ((13^(1/2)+7)^4)/1296 }

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